A motorboat travels 176 KM in 4 hours going upstream. It travels 288 KM going downstream in the same amount of time. What is the rate of the boat in still water and what is the rate of the current?

Find:

a) The rate of the boat in still water (km/h)
b) The rate of the current (km/h)

Solution:

Let X be the rate of boat in still water

Let Y be the rate of the current

4(x-y) = 176

4(x+y) = 288

Simplify by dividing both sides by 4 in both equations:

x-y = 44

x+y = 72

Adding the to equations to solve for X

2x= 116

Therefore, X = 58 km/h

Substituting the value of X in the equation (y=72-x)

Y = 72-58 = 14 km/h

Therefore,

a) The rate of the boat in still water: 58 km/h
b) The rate of the current: 14 km/h